Solve problems and analyse information about the force on current carrying conductors in magnetic fields

- As stated here, the force on a current carrying conductor can be expressed as:

\begin{align} F = BIl\sin{\theta} \end{align}

Where:

- $F$ is the magnitude of the Force ($N$)
- $B$ is the magnitude of the Magnetic Field Strength ($T$)
- $I$ is the magnitude of the Current ($A$)
- $l$ is the length of the Conductor within the field. ($m$)
- $\theta$ is the angle between the magnetic field and the conductor

The direction of these values can be found by the Right Hand Rule.

page revision: 1, last edited: 02 Mar 2011 09:06