Solve problems and analyse information about the force on current carrying conductors in magnetic fields
  • As stated here, the force on a current carrying conductor can be expressed as:
(1)
\begin{align} F = BIl\sin{\theta} \end{align}

Where:

  • $F$ is the magnitude of the Force ($N$)
  • $B$ is the magnitude of the Magnetic Field Strength ($T$)
  • $I$ is the magnitude of the Current ($A$)
  • $l$ is the length of the Conductor within the field. ($m$)
  • $\theta$ is the angle between the magnetic field and the conductor

The direction of these values can be found by the Right Hand Rule.