Solve problems and analyse information about the force on current carrying conductors in magnetic fields
• As stated here, the force on a current carrying conductor can be expressed as:
(1)
\begin{align} F = BIl\sin{\theta} \end{align}

Where:

• $F$ is the magnitude of the Force ($N$)
• $B$ is the magnitude of the Magnetic Field Strength ($T$)
• $I$ is the magnitude of the Current ($A$)
• $l$ is the length of the Conductor within the field. ($m$)
• $\theta$ is the angle between the magnetic field and the conductor

The direction of these values can be found by the Right Hand Rule.

page revision: 1, last edited: 02 Mar 2011 09:06