Solve problems related to the force between parallel current-carrying conductors
• As mentioned here, the magnitude of the force between two parallel conductors can be summed up Mathematically as:
(1)
\begin{align} F = k\frac{I_1I_2l}{d} \end{align}

Where:

• $B$ is the strength of the External Magnetic Field
• $k$ is Ampere's constant ($2.00 x 10^{-7}$)
• $I_1$ and $I_2$are the currents in the first conductor and the second conductor respectively($A$)
• $l$ is the common/shared length of the conductors ($m$)
• $d$ is the perpendicular distance between the two conductors ($m$)
• If the conductors carry current in the same direction, the force is attractive, and vice versa.
• This is because of the motor effect.
page revision: 6, last edited: 02 Mar 2011 08:53