Solve problems related to the force between parallel current-carrying conductors

- As mentioned here, the magnitude of the force between two parallel conductors can be summed up Mathematically as:

\begin{align} F = k\frac{I_1I_2l}{d} \end{align}

Where:

- $B$ is the strength of the External Magnetic Field
- $k$ is Ampere's constant ($2.00 x 10^{-7}$)
- $I_1$ and $I_2$are the currents in the first conductor and the second conductor respectively($A$)
- $l$ is the
**common/shared**length of the conductors ($m$) - $d$ is the perpendicular distance between the two conductors ($m$)

- If the conductors carry current in the same direction, the force is attractive, and vice versa.
- This is because of the motor effect.

page revision: 6, last edited: 02 Mar 2011 08:53