Charged Plates

- As mentioned previously, two parallel plates that have been oppositely charged produces a
**uniform electric field**. - This means that
**any charge at any place**between the two plates has the exact**same force**acting upon it.

To find out what the uniform Electric field strength is quantitatively:

- Recall that the force on a charged particle is given by: $F = qE$
- Where, E is the electric field strength

- Also, that Voltage is the change in potential energy per unit charge : $W = qV$
- As $W = Fd$:

\begin{equation} qV = Fd \end{equation}

(2)
\begin{equation} qV = qEd \end{equation}

(3)
\begin{equation} V = Ed \end{equation}

Therefore:

(4)\begin{align} E = \frac{V}{d} \end{align}

page revision: 1, last edited: 25 Apr 2011 05:30